편미분 관계식 관련 문제
질문
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5.6 번 증명 어떻게 해야하는지 모르겠어요 ㅠ
풀이
\[\left( \frac{\partial h}{\partial v}\right)_{s}= \left(\frac{T\partial s+v\partial P}{\partial v} \right)_{s} \]
\[=v \left(\frac{\partial P}{\partial v} \right)_{s} \]
\[=-v \left(\frac{\partial P}{\partial s} \right)_{v} \left(\frac{\partial s}{\partial v} \right)_{P}\]
\[=-v \left(\frac{\partial P}{\partial T} \right)_{v} \left(\frac{\partial T}{\partial s} \right)_{v} \left(\frac{\partial s}{\partial T} \right)_{P} \left(\frac{\partial T}{\partial v} \right)_{P}\]
\[=-v \frac{ \left(\frac{\partial s}{\partial T} \right)_{P}}{\left(\frac{\partial s}{\partial T} \right)_{v}} \left[\left(\frac{\partial P}{\partial T} \right)_{v}\left(\frac{\partial T}{\partial v} \right)_{P}\right]\]
\[ \left(\frac{\partial s}{\partial T} \right)_{P} = \frac{1}{T}\left(\frac{\partial h-v\partial P}{\partial T}\right)_{P}= \frac{1}{T}\left(\frac{\partial h}{\partial T}\right)_{P}= \frac{c_{P}}{T}\]
\[ \left(\frac{\partial s}{\partial T} \right)_{v} = \frac{1}{T}\left(\frac{\partial u+P\partial v}{\partial T}\right)_{v}= \frac{1}{T}\left(\frac{\partial u}{\partial T}\right)_{v}= \frac{c_{v}}{T}\]
\[\left( \frac{\partial h}{\partial v}\right)_{s}=-v \frac{ \left(\frac{\partial s}{\partial T} \right)_{P}}{\left(\frac{\partial s}{\partial T} \right)_{v}} \left[\left(\frac{\partial P}{\partial T} \right)_{v}\left(\frac{\partial T}{\partial v} \right)_{P}\right]\]
\[=v \frac{\frac{c_P}{T} }{ \frac{c_v}{T} } \left(\frac{\partial P}{\partial v}\right)_{T}=- \frac{\frac{c_P}{T} }{ \frac{c_v}{T} } \frac{1}{\frac{-1}{v} \left(\frac{\partial v}{\partial P}\right)_{T}}\]
\[-\frac{c_P}{c_v}\frac{1}{\kappa}\]
\[\left(\kappa = -\frac{1}{v}\left(\frac{\partial v}{\partial P}\right)_{T}=\beta_{T}\right)\]
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